y-y-cos-x-1-2y-2-trouve-la-solution-de-lequation-differentielle-

Question Number 154846 by SANOGO last updated on 22/Sep/21

y^{'} = \frac{y c o s (x)}{1 + 2 y^{2}}

t r o u v e l a s o l u t i o n d e l e q u a t i o n d i f f e r e n t i e l l e

Commented by tabata last updated on 22/Sep/21

\frac{d y}{d x} = \frac{y}{1 + 2 y^{2}} c o s (x)

\frac{1 + 2 y^{2}}{y} d y = c o s (x) d x

l n ∣ y ∣ + y^{2} = s i n (x) + c

∴ y^{2} + l n ∣ y ∣ - s i n (x) = c

⟨ M . T ⟩

Commented by SANOGO last updated on 22/Sep/21

m e r c i b i e n

Facebook Tweet Pin