z-Arg-a-b-pi-1-k-n-Z-b-0-k-lt-n-x-n-z-x-e-2k-a-bm-pii-To-prove-that-please- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 43894 by Rauny last updated on 17/Sep/18 ∣z∣=∣Arg(abπ)∣=1∧k,n∈Z∧b≠0⩽k<n:xn=z⇒x=e2k+abmπiToprovethat,please. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-109428Next Next post: Question-43897 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.