1-Prove-that-a-b-c-a-b-c-2-Find-all-x-R-that-satify-the-follow-ing-inequalities-i-x-2-4-lt-5-ii-x-x-2-lt-5-Help- Tinku Tara June 5, 2023 Others 0 Comments FacebookTweetPin Question Number 193137 by Mastermind last updated on 04/Jun/23 1)Provethat:∣a+b+c∣⩾∣a∣−∣b∣−∣c∣2)Findallx∈Rthatsatifythefollow−inginequalitiesi)∣x2−4∣<5ii)∣x∣+∣x+2∣<5Help! Answered by aba last updated on 04/Jun/23 ∣a∣=∣a+b+c−(b+c)∣⩽∣a+b+c∣+∣b+c∣(1)∣b+c∣⩽∣b∣+∣c∣⇒−∣b∣−∣c∣⩽−∣b+c∣(2)(1)+(2)⇒∣a∣−∣b∣−∣c∣⩽∣a+b+c∣✓ Answered by Rajpurohith last updated on 06/Jun/23 1)0⩽∣a∣=∣a+b+c−b−c∣⩽∣a+b+c∣+∣b∣+∣c∣⇒∣a∣−∣b∣−∣c∣⩽∣a+b+c∣2)(i)Twocasesarise∙x2⩽4⇒∣x2−4∣=4−x2<5⇒−1⩽x2whichisalwaystrue.sox2⩽4isfeasiblei.e,∣x∣⩽2.∙x2>4⇒∣x2−4∣=x2−4<5⇒x2<9⇒∣x∣<3hencethefinalregionorsolutionis∣x∣<3.(ii)∙Supposex⩾0then∣x∣=xand∣x+2∣=x+2sotheinequalitybecomesx+x+2<5⇒2x+2<5⇒x<32.Hence0⩽x<32isaregion.∙suppose−2⩽x<0⇒x+2⩾0⇒∣x∣=−xand∣x+2∣=x+2sotheinequalitybecomes−x+x+2<5whichistrue.so−2⩽x<0isalsoafeasibleregion.∙supposex<−2⇒∣x+2∣=−x−2and∣x∣=−xsotheinequalitybecomes−x−x−2<5⇒−2x<7⇒x>−72hencethefeasibleregionoftheinequalityis−72<x<32. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Solve-the-inequalities-x-1-2-gt-1-Thank-you-Next Next post: Question-193149 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.