Question Number 193111 by cortano12 last updated on 04/Jun/23
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Answered by math1234 last updated on 04/Jun/23
Answered by horsebrand11 last updated on 04/Jun/23
$$\:\Rightarrow\mathrm{2}\:=\:\frac{\mathrm{3}}{\mathrm{2}}\mathrm{a}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}\mathrm{a}\:;\:\mathrm{a}\geqslant\mathrm{0} \\ $$$$\:\Rightarrow\:\mathrm{3a}^{\mathrm{2}} +\mathrm{a}−\mathrm{4}=\mathrm{0} \\ $$$$\:\Rightarrow\left(\mathrm{3a}+\mathrm{4}\right)\left(\mathrm{a}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\:\Rightarrow\mathrm{a}=\mathrm{1} \\ $$