Question Number 193162 by ajfour last updated on 05/Jun/23
Commented by ajfour last updated on 05/Jun/23
$${Determine}\:\:\frac{{r}}{{R}}\:\:{in}\:{terms}\:{of}\:\mathrm{0}<{m}<\mathrm{1}. \\ $$
Commented by York12 last updated on 05/Jun/23
$${R}\:{is}\:{the}\:{radius}\:{of}\:{the}\:{biggest}\:{circle} \\ $$
Answered by mr W last updated on 17/Jun/23
Commented by mr W last updated on 17/Jun/23
$${r}+\sqrt{\mathrm{2}}{r}+{mR}=\mathrm{2}{R} \\ $$$$\Rightarrow\frac{{r}}{{R}}=\frac{\mathrm{2}−{m}}{\mathrm{1}+\sqrt{\mathrm{2}}} \\ $$