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Question Number 193116 by Mastermind last updated on 04/Jun/23
Show that for all a,b,c,d ∈ R with  a,b,c,d ≥ 0   1) (√(ab))(√(cd)) ≤ (1/4)(a^2 +b^2 +c^2 +d^2 )  2) (abcd)^(1/4)  ≤ (1/4)(a+b+c+d)    Help!
Showthatforalla,b,c,dRwitha,b,c,d01)abcd14(a2+b2+c2+d2)2)(abcd)1414(a+b+c+d)Help!
Answered by Subhi last updated on 04/Jun/23
1) 4(a^2 +b^2 +c^2 +d^2 )≥(a+b+c+d)^2   a+b+c+d≥4^4 (√(abcd))      (AM - GM)  (a+b+c+d)^2 ≥16(√(abcd))  4(a^2 +b^2 +c^2 +d^2 )≥16(√(abcd))  (1/4)(a^2 +b^2 +c^2 +d^2 )≥(√(ab)).(√(cd))
1)4(a2+b2+c2+d2)(a+b+c+d)2a+b+c+d44abcd(AMGM)(a+b+c+d)216abcd4(a2+b2+c2+d2)16abcd14(a2+b2+c2+d2)ab.cd
Commented by Subhi last updated on 04/Jun/23
4(a^2 +b^2 +c^2 +d^2 )≥(a+b+c+d)^2   (a+b+c+d)^2 =a^2 +b^2 +c^2 +d^2 +2cd+2ab+2ac+2ad+2bc+2bd  = a^2 +b^2 +c^2 +d^2 +2(ab+ac+ad+bc+bd+cd)   (i)  a^2 +b^2 +c^2 +d^2   a^2 +b^2 ≥2(√(a^2 .b^2 ))=2ab     (AM−GM)  b^2 +c^2 ≥2bc          ⇛  c^2 +d^2 ≥2cd  a^2 +d^2 ≥2ad        ⇛  b^2 +d^2 ≥2bd  a^2 +c^2 ≥2ac  sum the 5 equations  3(a^2 +b^2 +c^2 +d^2 )≥2(ab+bc+ac+ad+bd+cd)   (ii)  from (i) , (ii)  (a+b+c+d)^2 ≤4(a^2 +b^2 +c^2 +d^2 )
4(a2+b2+c2+d2)(a+b+c+d)2(a+b+c+d)2=a2+b2+c2+d2+2cd+2ab+2ac+2ad+2bc+2bd=a2+b2+c2+d2+2(ab+ac+ad+bc+bd+cd)(i)a2+b2+c2+d2a2+b22a2.b2=2ab(AMGM)b2+c22bcc2+d22cda2+d22adb2+d22bda2+c22acsumthe5equations3(a2+b2+c2+d2)2(ab+bc+ac+ad+bd+cd)(ii)from(i),(ii)(a+b+c+d)24(a2+b2+c2+d2)
Commented by Mastermind last updated on 04/Jun/23
Thank you so much
Thankyousomuch
Commented by Mastermind last updated on 04/Jun/23
Thank you my boss
Thankyoumyboss
Commented by Mastermind last updated on 04/Jun/23
What′s AM−GM?
WhatsAMGM?
Commented by Subhi last updated on 04/Jun/23
Arithmetic geometric mean inequality  its proof is below ↓
Arithmeticgeometricmeaninequalityitsproofisbelow
Answered by Subhi last updated on 04/Jun/23
proof for AM − GM  ((√a)−(√b))^2 ≥0  a+b−2(√(ab)) ≥0  ((a+b)/2)≥(√(ab))  ((a_1 +a_2 +.........a_n )/n)≥^n (√(a_1 .a_2 ......a_n ))  ((a+b+c+d)/4)≥^4 (√(abcd))
proofforAMGM(ab)20a+b2ab0a+b2aba1+a2+annna1.a2ana+b+c+d44abcd

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