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Find-the-value-of-x-from-the-following-equations-4-x-y-y-x-32-log-3-x-y-log-3-x-y-1-




Question Number 193295 by MATHEMATICSAM last updated on 09/Jun/23
Find the value of x from the following  equations:  4^((x/y) + (y/x))  = 32  log_3 (x − y) + log_3 (x + y) = 1
Findthevalueofxfromthefollowingequations:4xy+yx=32log3(xy)+log3(x+y)=1
Answered by BaliramKumar last updated on 09/Jun/23
2
2
Answered by Frix last updated on 09/Jun/23
x=py  4^(p+(1/p)) =4^(5/2)  ⇒ p=(1/2)∨p=2  x−y>0 ⇒ p>1 ⇒ p=2  log_3  (y) +log_3  (3y) =1  2log_3  y +1=1 ⇒ y=1 ⇒ x=2
x=py4p+1p=452p=12p=2xy>0p>1p=2log3(y)+log3(3y)=12log3y+1=1y=1x=2

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