Question Number 193280 by Mingma last updated on 09/Jun/23
Answered by AST last updated on 09/Jun/23
$$\mathrm{1000}\overset{\_\_\_\_} {{def}}+\overset{\_\_\_\_} {{abc}}=\mathrm{6000}\overset{\_\_\_\_} {{abc}}+\mathrm{6}\overset{\_\_\_\_} {{def}}\Rightarrow\frac{{def}}{{abc}}=\frac{\mathrm{5999}}{\mathrm{994}}=\frac{\mathrm{857}}{\mathrm{142}} \\ $$$$\Rightarrow\overset{\_\_\_\_\_\_\_\_} {{abcdef}}=\mathrm{142857} \\ $$
Commented by Mingma last updated on 09/Jun/23
Perfect