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0-1-cot-1-1-x-x-2-dx-




Question Number 85280 by Jakir Sarif Mondal last updated on 20/Mar/20
 ∫_( 0) ^1  cot^(−1) (1−x+x^2 ) dx =
10cot1(1x+x2)dx=
Answered by mind is power last updated on 20/Mar/20
=∫_0 ^1 tan^− ((1/(1−x(1−x))))dx  =∫_0 ^1 tan^− (((1−x+x)/(1−x(1−x))))dx=∫_0 ^1 (tan^− (1−x)+tan^− (x))dx  =2∫_0 ^1 tan^− (x)dx  =2[xtan^− (x)−ln(1+x^2 )]_0 ^1_    =(π/2)−ln(2)
=01tan(11x(1x))dx=01tan(1x+x1x(1x))dx=01(tan(1x)+tan(x))dx=201tan(x)dx=2[xtan(x)ln(1+x2)]01=π2ln(2)

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