0-100-sin-x-x-pi-dx- Tinku Tara June 14, 2023 None 0 Comments FacebookTweetPin Question Number 83225 by 09658867628 last updated on 28/Feb/20 ∫1000sin(x−[x])πdx= Commented by mathmax by abdo last updated on 29/Feb/20 A=∑n=099∫nn+1sin((x−n)π)dx=∑n=099∫nn+1sin(πx−nπ)dx=∑n=099∫nn+1(−1)nsin(πx)dx=∑n=099(−1)n[−1πcos(πx)]nn+1=1π∑n=099(−1)n+1{cos(n+1)π−cos(nπ)}=1π∑n=099(−1)n+1{(−1)n+1−(−1)n}=−2π∑n=099(−1)n×(−1)n+1=2π∑n=099(1)=200π Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-pi-2-cot-x-cot-x-tan-x-dx-Next Next post: 0-1-1-x-2-2x-cos-1-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.