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0-pi-2-4-sin-x-x-dx-




Question Number 43627 by peter frank last updated on 12/Sep/18
∫_( 0) ^(π^2 /4)  ((sin (√x))/( (√x))) dx =
π2/40sinxxdx=
Commented by math khazana by abdo last updated on 13/Sep/18
changement (√x)=t give  I = ∫_0 ^(π/2)  ((sint)/t) (2t)dt = 2 ∫_0 ^(π/2)  sin(t)dt  =2[−cost]_0 ^(π/2) =2 .
changementx=tgiveI=0π2sintt(2t)dt=20π2sin(t)dt=2[cost]0π2=2.

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