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0-pi-cos-7-x-sin-3x-dx-0-




Question Number 55777 by gunawan last updated on 04/Mar/19
∫_( 0) ^π   cos^7 x sin 3x dx = 0
π0cos7xsin3xdx=0
Answered by tanmay.chaudhury50@gmail.com last updated on 04/Mar/19
I=∫_0 ^π {cos(π−x)}^7 ×sin3(π−x)dx  =∫_0 ^π (−cos^7 x)×sin(3π−3x)dx  =−∫_0 ^π (cos^7 x)×sin3x  =−I  2I=0  I=0
I=0π{cos(πx)}7×sin3(πx)dx=0π(cos7x)×sin(3π3x)dx=0π(cos7x)×sin3x=I2I=0I=0
Commented by gunawan last updated on 04/Mar/19
Great Sir  Thank you
GreatSirThankyou

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