0-pi-cos-7-x-sin-3x-dx-0- Tinku Tara June 14, 2023 None 0 Comments FacebookTweetPin Question Number 55777 by gunawan last updated on 04/Mar/19 ∫π0cos7xsin3xdx=0 Answered by tanmay.chaudhury50@gmail.com last updated on 04/Mar/19 I=∫0π{cos(π−x)}7×sin3(π−x)dx=∫0π(−cos7x)×sin(3π−3x)dx=−∫0π(cos7x)×sin3x=−I2I=0I=0 Commented by gunawan last updated on 04/Mar/19 GreatSirThankyou Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-1-sin-2pi-x-dx-Next Next post: 2x-3-x-2-x-1-2-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.