1-e-log-x-dx-

Question Number 21467 by nawroozdawry last updated on 24/Sep/17

\underset{1}{\int^{e}} \log x d x =

Answered by $@ty@m last updated on 24/Sep/17

I = \int \log x . 1 d x

= \log x \int 1 d x - \int \frac{1}{x} . x d x

= x \log x - x + C

Missing \left or extra \right

= (e \log e - e) - (\log 1 - 1)

= e - e - 0 + 1

= 1

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