Question Number 51729 by shivshant0409 last updated on 30/Dec/18
$$\mathrm{81}^{\frac{\mathrm{1}}{\mathrm{4}}} ×\:\mathrm{9}^{\frac{\mathrm{3}}{\mathrm{2}}} ×\:\mathrm{27}^{\frac{\mathrm{4}}{\mathrm{3}}} =\:\_\_\_\_\_ \\ $$
Answered by aseerimad last updated on 30/Dec/18
$$\mathrm{81}^{\frac{\mathrm{1}}{\mathrm{4}}} ×\mathrm{9}^{\frac{\mathrm{3}}{\mathrm{2}}} ×\mathrm{27}^{\frac{\mathrm{4}}{\mathrm{3}}} \\ $$$$=\left(\mathrm{9}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{\mathrm{4}}} ×\left(\mathrm{3}^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} ×\left(\mathrm{3}^{\mathrm{3}} \right)^{\frac{\mathrm{4}}{\mathrm{3}}} \\ $$$$=\mathrm{9}^{\frac{\mathrm{1}}{\mathrm{2}}} ×\left(\mathrm{3}^{\mathrm{3}} \right)×\left(\mathrm{3}^{\mathrm{4}} \right) \\ $$$$=\mathrm{3}×\mathrm{27}×\mathrm{81} \\ $$$$=\mathrm{6561} \\ $$