Question Number 91507 by Zainal Arifin last updated on 01/May/20
$$\sqrt[{\mathrm{3}}]{\frac{−{a}^{\mathrm{6}} ×{b}^{\mathrm{3}} ×{c}^{\mathrm{21}} }{{c}^{\mathrm{9}} ×{a}^{\mathrm{12}} }}\:=\: \\ $$
Commented by jagoll last updated on 01/May/20
$$−\sqrt[{\mathrm{3}\:\:}]{\frac{{c}^{\mathrm{12}} ×{b}^{\mathrm{3}} }{{a}^{\mathrm{6}} }}\:=\:−\frac{{bc}^{\mathrm{4}} }{{a}^{\mathrm{2}} }\: \\ $$