A-and-B-can-complete-a-piece-of-work-in-12-days-and-24-days-respectively-After-A-had-worked-for-6-days-B-joined-him-and-then-they-completed-the-work-How-much-should-A-receive-as-his-share-from-th

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Question Number 95985 by mpym last updated on 29/May/20

$$\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{can}\mathrm{complete}\mathrm{a}\mathrm{piece}\mathrm{of}\mathrm{work}\mathrm{in}$$$$12\mathrm{days}\mathrm{and}24\mathrm{days}\mathrm{respectively}.\mathrm{After}$$$$\mathrm{A}\mathrm{had}\mathrm{worked}\mathrm{for}6\mathrm{days},\mathrm{B}\mathrm{joined}\mathrm{him},$$$$\mathrm{and}\mathrm{then}\mathrm{they}\mathrm{completed}\mathrm{the}\mathrm{work}.\mathrm{How}$$$$\mathrm{much}\mathrm{should}\mathrm{A}\mathrm{receive}\mathrm{as}\mathrm{his}\mathrm{share}\mathrm{from}$$$$\mathrm{the}\mathrm{total}\mathrm{amount}\mathrm{of}\mathrm{Rs}.180\mathrm{paid}\mathrm{for}$$$$\mathrm{completing}\mathrm{the}\mathrm{work}?$$

Answered by mr W last updated on 29/May/20

$$Adoes\frac{1}{12}workeachday$$$$Bdoes\frac{1}{24}workeachday$$$$Aworked6daysalone,thenAand$$$$Bworkxdaystogother:$$$$\frac{6+x}{12}+\frac{x}{24}=1$$$$\Rightarrow x=4$$$$totalworkdonebyA:\frac{10}{12}=\frac{5}{6}$$$$totalworkdonebyB:\frac{4}{24}=\frac{1}{6}$$$$Ashouldget\frac{5}{6}ofthetotalpayment,$$$$i.e.\frac{5}{6}\times 180=150Rs$$$$Bshouldget\frac{1}{6}ofthetotalpayment,$$$$i.e.\frac{1}{6}\times 180=30Rs$$

Commented by mr W last updated on 29/May/20

$$thisistheresultinmathematics.$$$$$$$$nowtheresultinpractice:$$$$Agets30RsandBgets150Rs,since$$$$Bisthenephewoftheboss.$$

Commented by bobhans last updated on 29/May/20

can C get everything, because C is a thug

Commented by i jagooll last updated on 29/May/20

$$\mathrm{hahahahaha}$$

Commented by som(math1967) last updated on 29/May/20

$$\mathrm{Haha}$$

Commented by john santu last updated on 29/May/20

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Answered by som(math1967) last updated on 29/May/20

$$\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{work}\mathrm{together}\mathrm{in}\mathrm{a}$$$$\mathrm{day}=\frac{1}{12}+\frac{1}{24}=\frac{1}{8}\mathrm{part}\mathrm{of}\mathrm{work}$$$$\mathrm{In}6\mathrm{day}\mathrm{A}\mathrm{complete}=\frac{6}{12}=\frac{1}{2}$$$$\mathrm{A},\mathrm{B}\mathrm{complete}=8\times \frac{1}{2}=4\mathrm{days}$$$${\mathrm{A}}^{\prime }\mathrm{s}\mathrm{work}:{\mathrm{B}}^{\prime }\mathrm{s}\mathrm{work}$$$$=10\times \frac{1}{12}:4\times \frac{1}{24}$$$$=\frac{5}{6}:\frac{1}{6}=5:1\therefore$$$$\therefore {\mathrm{A}}^{\prime }\mathrm{s}\mathrm{share}=\frac{5}{6}\times 180=\mathrm{Rs}150$$

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