Question Number 136901 by nadovic last updated on 27/Mar/21
$${A}\:{gold}\:{ore}\:{is}\:{found}\:{to}\:{have}\:{a}\:{purity} \\ $$$${of}\:\mathrm{70}{ppm}.\:{How}\:{much}\:{gold}\:{in}\:{grams} \\ $$$${can}\:{be}\:{recovered}\:{from}\:\mathrm{5}{kg}\:{of}\:{the}\:{ore}? \\ $$
Answered by Olaf last updated on 27/Mar/21
$${m}_{{pure}\:{gold}} \:=\:\tau{m}_{{ore}} \:=\:\mathrm{70}.\mathrm{10}^{−\mathrm{6}} ×\mathrm{5}.\mathrm{10}^{\mathrm{3}} \:=\:\mathrm{0},\mathrm{35}{g} \\ $$
Commented by nadovic last updated on 28/Mar/21
$${Thank}\:{you}\:{Sir} \\ $$