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A-number-is-multiplied-by-2-1-3-times-itself-and-then-61-is-subtracted-from-the-product-obtained-If-the-final-result-is-9200-then-the-number-is-




Question Number 24426 by dhandhaliyachandra@gmail.Com last updated on 17/Nov/17
A number is multiplied by 2(1/3) times  itself and then 61 is subtracted from  the product obtained. If the final result  is 9200, then the number is
$$\mathrm{A}\:\mathrm{number}\:\mathrm{is}\:\mathrm{multiplied}\:\mathrm{by}\:\mathrm{2}\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{times} \\ $$$$\mathrm{itself}\:\mathrm{and}\:\mathrm{then}\:\mathrm{61}\:\mathrm{is}\:\mathrm{subtracted}\:\mathrm{from} \\ $$$$\mathrm{the}\:\mathrm{product}\:\mathrm{obtained}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{final}\:\mathrm{result} \\ $$$$\mathrm{is}\:\mathrm{9200},\:\mathrm{then}\:\mathrm{the}\:\mathrm{number}\:\mathrm{is} \\ $$
Answered by ajfour last updated on 17/Nov/17
((7x^2 )/3)−61 = 9200  x^2 =(3/7)×9261 = 3×1323  x^2 =3×3×441 =3×3×21×21  x=63 .
$$\frac{\mathrm{7}{x}^{\mathrm{2}} }{\mathrm{3}}−\mathrm{61}\:=\:\mathrm{9200} \\ $$$${x}^{\mathrm{2}} =\frac{\mathrm{3}}{\mathrm{7}}×\mathrm{9261}\:=\:\mathrm{3}×\mathrm{1323} \\ $$$${x}^{\mathrm{2}} =\mathrm{3}×\mathrm{3}×\mathrm{441}\:=\mathrm{3}×\mathrm{3}×\mathrm{21}×\mathrm{21} \\ $$$${x}=\mathrm{63}\:. \\ $$

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