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If-2x-2-2p-13-x-2-0-is-exactly-divisible-by-x-3-then-the-value-of-p-is-




Question Number 68351 by mhmd last updated on 09/Sep/19
If 2x^2 +(2p−13)x+2=0 is exactly divisible  by x−3, then the value of p is
If2x2+(2p13)x+2=0isexactlydivisiblebyx3,thenthevalueofpis
Answered by $@ty@m123 last updated on 09/Sep/19
f(x)=2x^2 +(2p−13)x+2  ATQ,  f(3)=0  ⇒2×3^2 +(2p−13)×3+2=0  ⇒18+6p−39+2=0  ⇒6p=39−20  ⇒p=((19)/6)
f(x)=2x2+(2p13)x+2ATQ,f(3)=02×32+(2p13)×3+2=018+6p39+2=06p=3920p=196
Answered by Rasheed.Sindhi last updated on 10/Sep/19
An Other Way  (2x^2 +(2p−13)x+2 )÷(x−3)  By synthetic division:   (((3)),2,(2p−13),(       2)),(,,(       6),(6p−21)),(,2,(2p−7),(6p−19)) )  As x−3 is factor  ∴   6p−19=0⇒p=((19)/6)
AnOtherWay(2x2+(2p13)x+2)÷(x3)Bysyntheticdivision:(3)22p13266p2122p76p19)Asx3isfactor6p19=0p=196

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