Question Number 26498 by keshabthagunna3@gmail.com last updated on 26/Dec/17
$$\mathrm{If}\:\left(\mathrm{5}{x}+\mathrm{7}{y}\right)\::\:\left(\mathrm{3}{x}+\mathrm{11}{y}\right)=\:\mathrm{2}\::\:\mathrm{3},\:\mathrm{then}\: \\ $$$${x}\::\:{y}\:=\:\_\_\_\_. \\ $$
Answered by Rasheed.Sindhi last updated on 26/Dec/17
$$\frac{\mathrm{5x}+\mathrm{7y}}{\mathrm{3x}+\mathrm{11y}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\frac{\left(\mathrm{5x}+\mathrm{7y}\right)/\mathrm{y}}{\left(\mathrm{3x}+\mathrm{11y}\right)/\mathrm{y}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\frac{\mathrm{5}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+\mathrm{7}}{\mathrm{3}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+\mathrm{11}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\mathrm{15}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+\mathrm{21}=\mathrm{6}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+\mathrm{33} \\ $$$$\mathrm{9}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)=\mathrm{12} \\ $$$$\frac{\mathrm{x}}{\mathrm{y}}=\frac{\mathrm{12}}{\mathrm{9}}=\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\mathrm{x}:\mathrm{y}=\mathrm{4}:\mathrm{3} \\ $$
Commented by AHSoomro last updated on 26/Dec/17
$${Thanks}\:{B}\mathrm{oss} \\ $$