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If-a-b-c-are-in-AP-p-q-r-are-in-HP-and-ap-bq-cr-are-in-GP-then-p-r-r-p-is-equal-to-




Question Number 81731 by zainal tanjung last updated on 15/Feb/20
If  a, b, c are in AP;  p, q, r are in HP   and  ap, bq, cr  are in GP, then (p/r)+(r/p)  is equal to
Ifa,b,careinAP;p,q,rareinHPandap,bq,crareinGP,thenpr+rpisequalto
Commented by jagoll last updated on 15/Feb/20
(i) a,b,c in AP ⇒ 2b = a+c  (ii) ap, bq, cr in GP ⇒ (bq)^2 =apcr  (iii)p, q, r in HP ⇒ (1/q) = (2/((1/p)+(1/r)))  ⇒(1/p)+(1/r) = 2q
(i)a,b,cinAP2b=a+c(ii)ap,bq,crinGP(bq)2=apcr(iii)p,q,rinHP1q=21p+1r1p+1r=2q

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