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Question Number 54970 by Tip Top last updated on 15/Feb/19
If   a cos A=b cos B  in a △ABC,   then ∠C  is
IfacosA=bcosBinaABC,thenCis
Answered by $@ty@m last updated on 15/Feb/19
Given  (a/b)=((cos B)/(cos A))  ...(1)  We know that  (a/b)=((sin A)/(sin B))  ...(2)  from (1) and (2)  ((cos B)/(cos A))  =((sin A)/(sin B))  sin Acos A=sin Bcos B  sin 2A=sin 2B  ⇒A=B  or 2A=π−2B  from 2A=π−2B  we get  A=(π/2)−B  ⇒A+B=(π/2)  ⇒C=(π/2)
Givenab=cosBcosA(1)Weknowthatab=sinAsinB(2)from(1)and(2)cosBcosA=sinAsinBsinAcosA=sinBcosBsin2A=sin2BA=Bor2A=π2Bfrom2A=π2BwegetA=π2BA+B=π2C=π2

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