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If-A-lies-in-the-third-quadrant-and-3-tan-A-4-0-then-5-sin-2A-3-sin-A-4cos-A-




Question Number 20435 by pp75718276@gmail.com last updated on 26/Aug/17
If  A lies in the third quadrant and  3 tan A − 4 = 0, then   5 sin 2A + 3 sin A + 4cos A =
IfAliesinthethirdquadrantand3tanA4=0,then5sin2A+3sinA+4cosA=
Answered by Tinkutara last updated on 27/Aug/17
tan A = (4/3) ⇒ sin A = ((−4)/5), cos A = ((−3)/5)  ∵ π < A < ((3π)/2), both sine and cosine are  negative.  sin 2A = ((2 tan A)/(1 + tan^2  A)) = ((8/3)/(1 + ((16)/9))) = ((24)/(25))  ∴ 5×((24)/(25)) − 3×(4/5) − 4×(3/5) = 0
tanA=43sinA=45,cosA=35π<A<3π2,bothsineandcosinearenegative.sin2A=2tanA1+tan2A=831+169=24255×24253×454×35=0

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