If-C-0-C-1-C-2-C-n-256-then-2n-C-2-is-equal-to-

Question Number 25786 by gugalesweta@gmail.com last updated on 14/Dec/17

If C_{0} + C_{1} + C_{2} + \dots + C_{n} = 256, then

^{2 n} C_{2} is equal to

Answered by mrW1 last updated on 14/Dec/17

C_{0} + C_{1} + \dots + C_{n} = 2^{n} = 256 = 2^{8}

\Rightarrow n = 8

C_{2}^{2 n} = C_{2}^{16} = \frac{16 \times 15}{2 \times 1} = 120

Facebook Tweet Pin