If-cos-4x-1-cot-x-tan-x-dx-A-cos-4x-B-then-find-A-B-

Question Number 37189 by rahul 19 last updated on 10/Jun/18

If \int \frac{\cos 4 x + 1}{\cot x - \tan x} d x = A \cos 4 x + B, then

find A, B ?

Answered by math1967 last updated on 10/Jun/18

\int \frac{2 {c o s}^{2} 2 x}{\frac{{c o s}^{2} x - {s i n}^{2} x}{s i n x c o s x}} d x

\int \frac{2 {c o s}^{2} 2 x s i n x c o s x}{c o s 2 x} d x

\frac{1}{2} \int 2 s i n 2 x c o s 2 x d x

\frac{1}{2} \int s i n 4 x d x = - \frac{1}{8} c o s 4 x + c

∴ A = - \frac{1}{8}, B = c = s o m e c o n s t a n t

c o r r e c t ?

Commented by MJS last updated on 10/Jun/18

correct!

Facebook Tweet Pin