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If-in-a-ABC-8R-2-a-2-b-2-c-2-then-the-ABC-is-




Question Number 95512 by bagjamath last updated on 25/May/20
If  in a △ABC, 8R^2 = a^2 +b^2 +c^2 , then  the △ABC is
IfinaABC,8R2=a2+b2+c2,thentheABCis
Commented by som(math1967) last updated on 25/May/20
Rt angle triangle
Rtangletriangle
Commented by som(math1967) last updated on 25/May/20
a^2 +b^2 +c^2 =8R^2   4R^2 (sin^2 A+sin^2 B+sin^2 c)=8R^2   2sin^2 A+2sin^2 B+2sin^2 C=4  cos2A+cos2B+2cos^2 C=0  2cos(A+B)cos (A−B)+2cos^2 C=0  −cosCcos(A−B)+cos^2 C=0★  −cosC{cos(A−B)−cos(A+B)=0★  2cosCcos Acos B=0  eithercos C=0/cosB=0/cosA=0  ∴∠C=90 or∠B=90 or∠A=90  ★cos(A+B)=cos(π−C)=−cosC
a2+b2+c2=8R24R2(sin2A+sin2B+sin2c)=8R22sin2A+2sin2B+2sin2C=4cos2A+cos2B+2cos2C=02cos(A+B)cos(AB)+2cos2C=0cosCcos(AB)+cos2C=0cosC{cos(AB)cos(A+B)=02cosCcosAcosB=0eithercosC=0/cosB=0/cosA=0C=90orB=90orA=90cos(A+B)=cos(πC)=cosC
Commented by bagjamath last updated on 25/May/20
Very Nice  Thank You Sir
VeryNiceThankYouSir

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