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If-Px-b-c-Qy-c-a-Rz-a-b-then-find-Pax-Qby-Rcz-




Question Number 14128 by chux last updated on 28/May/17
If  ((Px)/((b−c))) = ((Qy)/((c−a))) = ((Rz)/((a−b))) , then find  Pax + Qby + Rcz.
$$\mathrm{If}\:\:\frac{\mathrm{P}{x}}{\left({b}−{c}\right)}\:=\:\frac{\mathrm{Q}{y}}{\left({c}−{a}\right)}\:=\:\frac{\mathrm{R}{z}}{\left({a}−{b}\right)}\:,\:\mathrm{then}\:\mathrm{find} \\ $$$$\mathrm{P}{ax}\:+\:\mathrm{Q}{by}\:+\:\mathrm{R}{cz}. \\ $$
Answered by ajfour last updated on 28/May/17
let  ((Px)/(b−c))=((Qy)/(c−a))=((Rz)/(a−b))=m  (say)  to find:     Pax+Qby+Rcz=    ma(b−c)+mb(c−a)+mc(a−b)       =m(ab−ac+bc−ab+ac−bc)       =0 .
$${let}\:\:\frac{{Px}}{{b}−{c}}=\frac{{Qy}}{{c}−{a}}=\frac{{Rz}}{{a}−{b}}={m}\:\:\left({say}\right) \\ $$$${to}\:{find}:\:\:\: \\ $$$${Pax}+{Qby}+{Rcz}= \\ $$$$\:\:{ma}\left({b}−{c}\right)+{mb}\left({c}−{a}\right)+{mc}\left({a}−{b}\right) \\ $$$$\:\:\:\:\:={m}\left({ab}−{ac}+{bc}−{ab}+{ac}−{bc}\right) \\ $$$$\:\:\:\:\:=\mathrm{0}\:. \\ $$
Commented by Joseph Paul Byaraujo. last updated on 29/May/17
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