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If-the-constant-forces-2i-5j-6k-and-i-2j-k-act-on-a-particle-due-to-which-it-is-displaced-from-a-point-A-4-3-2-to-a-point-B-6-1-3-then-the-work-done-by-the-forces-is-




Question Number 58056 by Salomon M. last updated on 17/Apr/19
If the constant forces 2i−5j+6k and  −i+2j−k act on a particle due to which  it is displaced from a point A(4,−3,−2)  to a point B(6, 1,−3), then the work   done by the forces is
Iftheconstantforces2i5j+6kandi+2jkactonaparticleduetowhichitisdisplacedfromapointA(4,3,2)toapointB(6,1,3),thentheworkdonebytheforcesis
Answered by tanmay last updated on 17/Apr/19
OA^→ =4i−3j−2k  OB^→ =6i+j−3k  displacement=AB^→ =OB^→ −OA^→   AB^→ =(6i+j−3k)−(4i−3j−2k)  AB^→ =2i+4j−k  F_1 ^→ +F_2 ^→  =(2i−5j+6k)+(−i+2j−k)  F_1 ^→ +F_2 ^→ =i−3j+5k  W=(F_1 ^→ +F_2 ^→ ).(AB^→ )     =(i−3j+5k).(2i+4j−k)     =2×1+(−3)×4+5×(−1)  =2−12−5  =−15 unit
OA=4i3j2kOB=6i+j3kdisplacement=AB=OBOAAB=(6i+j3k)(4i3j2k)AB=2i+4jkF1+F2=(2i5j+6k)+(i+2jk)F1+F2=i3j+5kW=(F1+F2).(AB)=(i3j+5k).(2i+4jk)=2×1+(3)×4+5×(1)=2125=15unit

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