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If-the-roots-of-9x-2-2x-7-0-are-2-more-than-the-roots-of-ax-2-bx-c-0-then-4a-2b-c-can-be-

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Question Number 35534 by jonesme last updated on 20/May/18
If the roots of 9x^2 −2x+7=0 are 2 more than the roots of ax^2 +bx+c=0, then 4a−2b+c can be
Iftherootsof9x2−2x+7=0are2morethantherootsofax2+bx+c=0,then4a−2b+ccanbe
Answered by ajfour last updated on 20/May/18
⇒ a(x+2)^2 +b(x+2)+c = 9x^2 −2x+7 ⇒ a=9 , 4a+b=−2 , 4a+2b+c=7 ⇒ b=−38 , c=47 ⇒ 4a−2b+c =36+76+47 =159 .
⇒a(x+2)2+b(x+2)+c=9x2−2x+7⇒a=9,4a+b=−2,4a+2b+c=7⇒b=−38,c=47⇒4a−2b+c=36+76+47=159.

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