Question Number 54421 by gunawan last updated on 03/Feb/19

Commented by tanmay.chaudhury50@gmail.com last updated on 04/Feb/19

Commented by gunawan last updated on 05/Feb/19

Answered by tanmay.chaudhury50@gmail.com last updated on 03/Feb/19
![c=ip+jq+kr b=j a=ix+jy+kz a×c=b [i j k] [x y z] [p q r] i(yr−qz)−j(xr−pz)+k(xq−py)=j [given] yr−qz=0 (y/q)=(z/r)....(1)eqn −(xr−pz)=1.....(2)eqn (xq−py)=0 (x/p)=(y/q) so (x/p)=(y/q)=(z/r)=(1/α) p=xα q=yα r=zα −(xr−pz)=1 −x(zα)+(xα)z=1 some thing wrong pls check question...](https://www.tinkutara.com/question/Q54432.png)
Answered by ajfour last updated on 03/Feb/19
