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In-a-ABC-B-pi-3-and-C-pi-4-Let-D-divide-BC-internally-in-the-ratio-1-3-Then-sin-BAD-sin-CAD-equals-




Question Number 113808 by deepraj123 last updated on 15/Sep/20
In a △ABC , ∠B=(π/3) and ∠C=(π/4). Let  D divide BC internally in the ratio  1 : 3. Then ((sin ∠BAD)/(sin ∠CAD)) equals
$$\mathrm{In}\:\mathrm{a}\:\bigtriangleup{ABC}\:,\:\angle{B}=\frac{\pi}{\mathrm{3}}\:\mathrm{and}\:\angle{C}=\frac{\pi}{\mathrm{4}}.\:\mathrm{Let} \\ $$$${D}\:\mathrm{divide}\:{BC}\:\mathrm{internally}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{1}\::\:\mathrm{3}.\:\mathrm{Then}\:\frac{\mathrm{sin}\:\angle{BAD}}{\mathrm{sin}\:\angle{CAD}}\:\mathrm{equals} \\ $$

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