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In-a-triangle-the-length-of-the-two-larger-sides-are-24-and-22-respectively-If-the-angles-are-in-AP-then-the-third-side-is-




Question Number 41079 by nadeem last updated on 01/Aug/18
In a triangle the length of the two  larger sides are 24 and 22, respectively.  If the angles are in AP, then the third  side is
Inatrianglethelengthofthetwolargersidesare24and22,respectively.IftheanglesareinAP,thenthethirdsideis
Answered by tanmay.chaudhury50@gmail.com last updated on 01/Aug/18
let angles are A−∝,A,A+∝  A−∝+A+A+∝=180^o   3A=180^o    A=60^o   unknoen side be x  cosA=((x^2 +24^2 −22^2 )/(2x.24))  (1/2)=((x^2 +46×2)/(2.x.24))  24x=x^2 +92  x^2 −24x+92=0  x=((24−(√(576−368)) )/2)=((24−14.42)/2)=((9.58)/2)=4.79  we can not take ((24+(√(576−368)) )/2) since  24 is greatest side as per question  cos(A−∝)=((24^2 +22^2 −4.79^2 )/(2.24.22))  A−∝=cos^(−1) (((24^2 +22^2 −4.79^2 )/(2.24.22)))  A+.∝=cos^(−1) (((22^2 +4.79^2 −24^2 )/(2.22.4.79)))
letanglesareA,A,A+A+A+A+∝=180o3A=180oA=60ounknoensidebexcosA=x2+2422222x.2412=x2+46×22.x.2424x=x2+92x224x+92=0x=245763682=2414.422=9.582=4.79wecannottake24+5763682since24isgreatestsideasperquestioncos(A)=242+2224.7922.24.22A∝=cos1(242+2224.7922.24.22)A+.∝=cos1(222+4.7922422.22.4.79)

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