Question Number 94629 by Vishal Sharma last updated on 20/May/20
$$\mathrm{In}\:\bigtriangleup{ABC},\:{a}=\sqrt{\mathrm{3}}+\mathrm{1},\:{B}=\mathrm{30}°,\:{C}=\mathrm{45}°, \\ $$$$\mathrm{then}\:{c}\:=\:\_\_\_\_. \\ $$
Answered by i jagooll last updated on 20/May/20
$$\frac{\mathrm{c}}{\mathrm{sin}\:\mathrm{45}^{\mathrm{o}} }\:=\:\frac{\mathrm{a}}{\mathrm{sin}\:\mathrm{105}^{\mathrm{o}} } \\ $$