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pi-2-pi-2-sin-log-x-x-2-1-dx-




Question Number 34446 by dilanho last updated on 06/May/18
 ∫_(−π/2) ^(π/2)  sin {log (x+(√(x^2 +1)) )} dx =
π/2π/2sin{log(x+x2+1)}dx=
Commented by math khazana by abdo last updated on 06/May/18
let put I = ∫_(−(π/2)) ^(π/2)  sin{ln(x +(√(x^2 +1)) )}dx  I  = ∫_(−(π/2)) ^(π/2)  sin(argshx)dx  let put argshx=t ⇔  x=sh(t) ⇒ I  = ∫_(−argsh((π/2))) ^(argsh((π/2)))  sint  cht dt  I  =0 because the function t →sint cht is odd.
letputI=π2π2sin{ln(x+x2+1)}dxI=π2π2sin(argshx)dxletputargshx=tx=sh(t)I=argsh(π2)argsh(π2)sintchtdtI=0becausethefunctiontsintchtisodd.

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