Question Number 63834 by gunawan last updated on 10/Jul/19
$$\mathrm{The}\:\mathrm{14th}\:\mathrm{term}\:\mathrm{from}\:\mathrm{the}\:\mathrm{end}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion} \\ $$$$\mathrm{of}\:\left(\sqrt{{x}}\:−\:\sqrt{{y}}\right)^{\mathrm{17}} \:\mathrm{is} \\ $$
Commented by kaivan.ahmadi last updated on 10/Jul/19
$${T}_{\mathrm{14}} =\begin{pmatrix}{\mathrm{17}}\\{\mathrm{13}}\end{pmatrix}\left(\sqrt{{x}}\right)^{\mathrm{17}−\mathrm{13}} \left(\sqrt{{y}}\right)^{\mathrm{13}} \\ $$
Commented by Prithwish sen last updated on 10/Jul/19
$$\mathrm{I}\:\mathrm{think}\:\mathrm{it}\:\mathrm{will}\:\mathrm{be}\:\mathrm{18}−\mathrm{14}+\mathrm{1}\:=\:\mathrm{5}^{\mathrm{th}} \:\mathrm{term} \\ $$