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Question Number 13490 by aamaguestt last updated on 20/May/17
The area of a rectangle is 255 m^2 . If  its length is decreased by 1 m, it   becomes a square. The perimeter of  the square is ____ m.
Theareaofarectangleis255m2.Ifitslengthisdecreasedby1m,itbecomesasquare.Theperimeterofthesquareis____m.
Answered by ajfour last updated on 20/May/17
x(x+1)=255  x^2 +x−255=0  x=((−1+(√(1+4(255))))/2)  perimeter of square = 4x         =(2(√(1021))−2)m ≈ 61.906m .
x(x+1)=255x2+x255=0x=1+1+4(255)2perimeterofsquare=4x=(210212)m61.906m.
Commented by aamaguestt last updated on 20/May/17
I slolve like this but the answer in the application  is 64 m.  y
Islolvelikethisbuttheanswerintheapplicationis64m.y
Commented by prakash jain last updated on 20/May/17
I think question meant that length  decreased by 1 with fixed perimeter  so width increases by 1.  (x−1)(x+1)=255  x^2 −1=255  x^2 =256⇒x=16  4x=64  rectangle length=17, width=15  rectangle area=255
Ithinkquestionmeantthatlengthdecreasedby1withfixedperimetersowidthincreasesby1.(x1)(x+1)=255x21=255x2=256x=164x=64rectanglelength=17,width=15rectanglearea=255
Commented by ajfour last updated on 20/May/17
good thought.i dint either like  the answer.
goodthought.idinteitherliketheanswer.

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