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The-digit-at-unit-s-place-in-the-number-17-1995-11-1995-7-1995-is-

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Question Number 86499 by ram roop sharma last updated on 29/Mar/20
The digit at unit′s place in the number 17^(1995) + 11^(1995) −7^(1995) is
Thedigitatunit′splaceinthenumber171995+111995−71995is
Commented by Serlea last updated on 29/Mar/20
17^(1995) +11^(1995) −7^(1995) =11^(1995) (mod10) {17=7(mod10)} 11=1(mod) 11^(1995) =1(mod) 1
171995+111995−71995=111995(mod10){17=7(mod10)}11=1(mod)111995=1(mod)1
Answered by redmiiuser last updated on 29/Mar/20
1 as we know that the unit digit of 17^5 and 7^5 and 7 and that of 11^5 is 1 so same with 17^(1995) ,7^(1995) and 11^(1995) the unit digits are 7 and 1. now 7+1−7=1
1asweknowthattheunitdigitof175and75and7andthatof115is1sosamewith171995,71995and111995theunitdigitsare7and1.now7+1−7=1

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