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Question Number 15194 by arnabpapu550@gmail.com last updated on 08/Jun/17
The equation  determinant (((x−a),(x−b),(x−c)),((x−b),(x−c),(x−a)),((x−c),(x−a),(x−b)))=0,  where a, b, c are different, is satisfied by
Theequation|xaxbxcxbxcxaxcxaxb|=0,wherea,b,caredifferent,issatisfiedby
Commented by prakash jain last updated on 08/Jun/17
  determinant (((x−a),(x−b),(x−c)),((x−b),(x−c),(x−a)),((x−c),(x−a),(x−b)))=0,  R1=R1+R2+R3    determinant (((3x−a−b−c),(3x−a−b−c),(3x−c−b−a)),((x−b),(x−c),(x−a)),((x−c),(x−a),(x−b)))=0,   (3x−a−b−c) determinant ((1,1,1),((x−b),(x−c),(x−a)),((x−c),(x−a),(x−b)))=0,  C1=C1−C2,C2=C2−C3   (3x−a−b−c) determinant ((0,0,1),((c−b),(a−c),(x−a)),((a−c),(b−a),(x−b)))=0,  3x−a−b−c=0⇒x=((a+b+c)/3)
|xaxbxcxbxcxaxcxaxb|=0,R1=R1+R2+R3|3xabc3xabc3xcbaxbxcxaxcxaxb|=0,(3xabc)|111xbxcxaxcxaxb|=0,C1=C1C2,C2=C2C3(3xabc)|001cbacxaacbaxb|=0,3xabc=0x=a+b+c3
Commented by arnabpapu550@gmail.com last updated on 08/Jun/17
excellent!
excellent!

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