Menu Close

The-exponent-of-12-in-100-is-




Question Number 5824 by Bc160200609 last updated on 30/May/16
The exponent of  12 in  100!  is
Theexponentof12in100!is
Commented by Yozzii last updated on 30/May/16
12^(48) =2^(96) 3^(48)  but I haven′t figured  out yet how to show this.  The isolation of powers of 2 and 3  in the product of 100! is required.  12=2^2 ×3. There may be a simple  method...
1248=296348butIhaventfiguredoutyethowtoshowthis.Theisolationofpowersof2and3intheproductof100!isrequired.12=22×3.Theremaybeasimplemethod
Commented by prakash jain last updated on 30/May/16
Exponent of 2=⌊((100)/2)⌋+⌊((100)/2^2 )⌋+...+⌊((100)/2^6 )⌋  =50+25+12+6+3+1=97  Exponent of 3=⌊((100)/3)⌋+⌊((100)/3^2 )⌋+⌊((100)/3^3 )⌋+⌊((100)/3^4 )⌋  =33+11+3+1=48  12=2^2 ×3  So highest power of 12=48  12^(48) =2^(96) ×3^(48)
Exponentof2=1002+10022++10026=50+25+12+6+3+1=97Exponentof3=1003+10032+10033+10034=33+11+3+1=4812=22×3Sohighestpowerof12=481248=296×348
Commented by Yozzii last updated on 30/May/16
Is there an explanation for the  forumula?
Isthereanexplanationfortheforumula?
Commented by prakash jain last updated on 01/Jun/16
Every multiple of 2 in 1 to 100 adds 1 to  exponent of 100!  Every multiple of 4 in 1−100 adds 2 to  exponent of 100!  and so on.  so exponent of 2 in 100!  =⌊((100)/2)⌋+⌊((100)/4)⌋+⌊((100)/8)⌋+⌊((100)/(16))⌋+⌊((100)/(32))⌋+⌊((100)/(64))⌋  =50+25+12+6+3+1=97
Everymultipleof2in1to100adds1toexponentof100!Everymultipleof4in1100adds2toexponentof100!andsoon.soexponentof2in100!=1002+1004+1008+10016+10032+10064=50+25+12+6+3+1=97
Commented by Yozzii last updated on 01/Jun/16
I see. Thanks!
Isee.Thanks!

Leave a Reply

Your email address will not be published. Required fields are marked *