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The-HCF-of-x-1-x-2-4-and-x-2-1-x-2-is-




Question Number 104275 by mubarakagulamhusain last updated on 20/Jul/20
The HCF of (x−1)(x^2 −4) and   (x^2 −1)(x+2)  is
$$\mathrm{The}\:\mathrm{HCF}\:\mathrm{of}\:\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} −\mathrm{4}\right)\:\mathrm{and}\: \\ $$$$\left({x}^{\mathrm{2}} −\mathrm{1}\right)\left({x}+\mathrm{2}\right)\:\:\mathrm{is} \\ $$
Commented by 1549442205PVT last updated on 20/Jul/20
you can tell me what is brief word ”HCF”?
$$\mathrm{you}\:\mathrm{can}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{what}\:\mathrm{is}\:\mathrm{brief}\:\mathrm{word}\:''\mathrm{HCF}''? \\ $$$$ \\ $$
Commented by Rasheed.Sindhi last updated on 20/Jul/20
Highest Common Factor
$${Highest}\:{Common}\:{Factor} \\ $$
Answered by Rasheed.Sindhi last updated on 20/Jul/20
(x−1)(x^2 −4)=(x−1)(x−2)(x+2)  (x^2 −1)(x+2)=(x−1)(x+1)(x+2)_(−)    Common factors:(x−1), (x+2)   Highest C. Factors:(x−1)(x+2)   OR                                      x^2 +x−2
$$\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} −\mathrm{4}\right)=\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}+\mathrm{2}\right) \\ $$$$\underset{−} {\left({x}^{\mathrm{2}} −\mathrm{1}\right)\left({x}+\mathrm{2}\right)=\left({x}−\mathrm{1}\right)\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)} \\ $$$$\:{Common}\:{factors}:\left({x}−\mathrm{1}\right),\:\left({x}+\mathrm{2}\right) \\ $$$$\:{Highest}\:{C}.\:{Factors}:\left({x}−\mathrm{1}\right)\left({x}+\mathrm{2}\right) \\ $$$$\:{OR}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} +{x}−\mathrm{2} \\ $$

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