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Question Number 86663 by ram roop sharma last updated on 30/Mar/20
The matrix A satisfying the equation   [(1,3),(0,1) ]A =  [(1,(    1)),(0,(−1)) ] is
$$\mathrm{The}\:\mathrm{matrix}\:{A}\:\mathrm{satisfying}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\begin{bmatrix}{\mathrm{1}}&{\mathrm{3}}\\{\mathrm{0}}&{\mathrm{1}}\end{bmatrix}{A}\:=\:\begin{bmatrix}{\mathrm{1}}&{\:\:\:\:\mathrm{1}}\\{\mathrm{0}}&{−\mathrm{1}}\end{bmatrix}\:\mathrm{is} \\ $$
Commented by Prithwish Sen 1 last updated on 30/Mar/20
 [((1       4)),((0   −1)) ]
$$\begin{bmatrix}{\mathrm{1}\:\:\:\:\:\:\:\mathrm{4}}\\{\mathrm{0}\:\:\:−\mathrm{1}}\end{bmatrix} \\ $$
Answered by Kunal12588 last updated on 30/Mar/20
A= [(1,3),(0,1) ]^(−1)  [(1,(     1)),(0,(−1)) ]  A= [(1,(−3)),(0,(     1)) ] [(1,(     1)),(0,(−1)) ]  A= [(1,(     4)),(0,(−1)) ]
$${A}=\begin{bmatrix}{\mathrm{1}}&{\mathrm{3}}\\{\mathrm{0}}&{\mathrm{1}}\end{bmatrix}^{−\mathrm{1}} \begin{bmatrix}{\mathrm{1}}&{\:\:\:\:\:\mathrm{1}}\\{\mathrm{0}}&{−\mathrm{1}}\end{bmatrix} \\ $$$${A}=\begin{bmatrix}{\mathrm{1}}&{−\mathrm{3}}\\{\mathrm{0}}&{\:\:\:\:\:\mathrm{1}}\end{bmatrix}\begin{bmatrix}{\mathrm{1}}&{\:\:\:\:\:\mathrm{1}}\\{\mathrm{0}}&{−\mathrm{1}}\end{bmatrix} \\ $$$${A}=\begin{bmatrix}{\mathrm{1}}&{\:\:\:\:\:\mathrm{4}}\\{\mathrm{0}}&{−\mathrm{1}}\end{bmatrix} \\ $$

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