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Question Number 63539 by REHEMAABDDUL last updated on 05/Jul/19
The minimum value of 2x^2 −3x+2 is ___.
$$\mathrm{The}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{2}{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}\:\mathrm{is}\:\_\_\_. \\ $$
Commented by Prithwish sen last updated on 05/Jul/19
= 2(x−(3/4))^2 +(7/8)  ∵ 2(x−(3/4))^2 ≥0  ∴ the minimum value = (7/8)
$$=\:\mathrm{2}\left(\mathrm{x}−\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{2}} +\frac{\mathrm{7}}{\mathrm{8}} \\ $$$$\because\:\mathrm{2}\left(\mathrm{x}−\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{2}} \geqslant\mathrm{0} \\ $$$$\therefore\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:=\:\frac{\mathrm{7}}{\mathrm{8}} \\ $$
Commented by meme last updated on 05/Jul/19
a=2>0  the minimum is x=(3/4)
$${a}=\mathrm{2}>\mathrm{0} \\ $$$${the}\:{minimum}\:{is}\:{x}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$
Answered by Rio Michael last updated on 05/Jul/19
 min value = ((4ac−b^2 )/(4a))    min val= ((4(2)(2)−(−3)^2 )/(4(2)))                       = (7/8)
$$\:{min}\:{value}\:=\:\frac{\mathrm{4}{ac}−{b}^{\mathrm{2}} }{\mathrm{4}{a}} \\ $$$$\:\:{min}\:{val}=\:\frac{\mathrm{4}\left(\mathrm{2}\right)\left(\mathrm{2}\right)−\left(−\mathrm{3}\right)^{\mathrm{2}} }{\mathrm{4}\left(\mathrm{2}\right)} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\frac{\mathrm{7}}{\mathrm{8}} \\ $$

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