The-number-of-possible-pairs-of-successive-prime-numbers-such-that-each-of-them-is-greater-than-40-and-their-sum-is-atmost-100-is-

Question Number 14572 by chux last updated on 02/Jun/17

The number of possible pairs of

successive prime numbers such that

each of them is greater than 40 and

their sum is atmost 100 is

Commented by mrW1 last updated on 02/Jun/17

53 + 59 = 112

47 + 53 = 100

43 + 47 = 90

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