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Question Number 32418 by hizmzm1 last updated on 24/Mar/18
The number of real roots or  x^8 − x^5 − x + 1 = 0 is equal to
$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{real}\:\mathrm{roots}\:\mathrm{or} \\ $$$${x}^{\mathrm{8}} −\:{x}^{\mathrm{5}} −\:{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$
Commented by hizmzm1 last updated on 27/Mar/18
1^8 −1^5 −1+1=0, hence 1 is root of eqn. then why answer for   no. of roots is zero??
$$\mathrm{1}^{\mathrm{8}} −\mathrm{1}^{\mathrm{5}} −\mathrm{1}+\mathrm{1}=\mathrm{0},\:\mathrm{hence}\:\mathrm{1}\:\mathrm{is}\:\mathrm{root}\:\mathrm{of}\:\mathrm{eqn}.\:\mathrm{then}\:\mathrm{why}\:\mathrm{answer}\:\mathrm{for}\: \\ $$$$\mathrm{no}.\:\mathrm{of}\:\mathrm{roots}\:\mathrm{is}\:\mathrm{zero}?? \\ $$$$ \\ $$

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