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The-number-of-real-roots-or-x-8-x-5-x-1-0-is-equal-to-




Question Number 32418 by hizmzm1 last updated on 24/Mar/18
The number of real roots or  x^8 − x^5 − x + 1 = 0 is equal to
Thenumberofrealrootsorx8x5x+1=0isequalto
Commented by hizmzm1 last updated on 27/Mar/18
1^8 −1^5 −1+1=0, hence 1 is root of eqn. then why answer for   no. of roots is zero??
18151+1=0,hence1isrootofeqn.thenwhyanswerforno.ofrootsiszero??

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