The-probability-that-in-a-random-arrangement-of-the-letters-of-the-word-UNIVERSITY-the-two-I-do-not-come-together-is-

Question Number 99141 by babar last updated on 18/Jun/20

The probability that in a random

arrangement of the letters of the word

^{'} {UNIVERSITY}^{'} the two I^{'} do not come

together is

Answered by bramlex last updated on 19/Jun/20

n (S) = \frac{10!}{2!}; n (A) = 9 \times 8!

P (A) = \frac{n (A)}{n (S)} = \frac{9 \times 8!}{(\frac{10!}{2!})} = \frac{2 \times 9}{10 \times 9} = \frac{1}{5}

Commented by bemath last updated on 19/Jun/20

it should be P (A^{c}) = 1 - P (A) = \frac{4}{5}

Commented by bramlex last updated on 19/Jun/20

o h y e s .

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