Menu Close

The-solution-of-the-equation-x-1-x-4-x-7-x-28-155-is-given-by-x-




Question Number 110016 by ZiYangLee last updated on 26/Aug/20
The solution of the equation  (x+1)+(x+4)+(x+7)+...+(x+28)=155  is given by x = _____.
Thesolutionoftheequation(x+1)+(x+4)+(x+7)++(x+28)=155isgivenbyx=_____.
Answered by Aziztisffola last updated on 26/Aug/20
 10x+1+4+7+...+28=155   10x+((1+28)/2)×10=155   10x+5×29=155   10x+145=155   10x=10 ⇒x=1
10x+1+4+7++28=15510x+1+282×10=15510x+5×29=15510x+145=15510x=10x=1
Commented by aurpeyz last updated on 26/Aug/20
pls how did you get 10x in the first line?
plshowdidyouget10xinthefirstline?
Commented by Aziztisffola last updated on 26/Aug/20
x+x+...+x=10x  1+ 4+...+28_(⌣_(10 terms) )
x+x++x=10x1+4++2810terms
Answered by som(math1967) last updated on 26/Aug/20
x+x+....10term+(1+4+..+28)=155  10x+((10)/2){2×1+(10−1)×3}=155  ⇒10x+145=155  ∴x=((10)/(10))=1ans
x+x+.10term+(1+4+..+28)=15510x+102{2×1+(101)×3}=15510x+145=155x=1010=1ans
Answered by floor(10²Eta[1]) last updated on 26/Aug/20
notice that (1, 4, 7, .., 28) is an AP with   ratio=3  a_n =a_1 +(n−1)r  28=1+(n−1)3⇒n=10  sum of the terms of a AP is  (((a_1 +a_n )n)/2)=(((1+28).10)/2)=145  ∴ (x+1)+(x+4)+(x+7)+...+(x+28)  =10x+145=155⇒10x=10⇒x=1
noticethat(1,4,7,..,28)isanAPwithratio=3an=a1+(n1)r28=1+(n1)3n=10sumofthetermsofaAPis(a1+an)n2=(1+28).102=145(x+1)+(x+4)+(x+7)++(x+28)=10x+145=15510x=10x=1
Commented by aurpeyz last updated on 26/Aug/20
how is number of terms equal to 10?
howisnumberoftermsequalto10?
Commented by floor(10²Eta[1]) last updated on 27/Aug/20
3 and 4 line is the formula for the   general term of an AP
3and4lineistheformulaforthegeneraltermofanAP

Leave a Reply

Your email address will not be published. Required fields are marked *