Question Number 11943 by 010418 last updated on 06/Apr/17
$$\mathrm{The}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$${x}^{\mathrm{2}} +\:{x}\:+\:\mathrm{1}\:=\:\mathrm{1}\:\:\:\mathrm{is} \\ $$
Answered by ajfour last updated on 06/Apr/17
$$\Rightarrow\:{x}\left({x}+\mathrm{1}\right)=\mathrm{0} \\ $$$${this}\:{happens}\:{when}\: \\ $$$${x}=\mathrm{0},\:{and}\:{x}=−\mathrm{1}\:. \\ $$
Commented by ajfour last updated on 06/Apr/17
