The-square-root-of-x-m-2-n-2-x-n-2-2mn-x-n-2-is-

Question Number 44231 by Mawitea Cck last updated on 24/Sep/18

The square root of x^{m^{2} - n^{2}} \cdot x^{n^{2} + 2 m n} \cdot x^{n^{2}} is

Answered by Joel578 last updated on 24/Sep/18

\sqrt{x^{(m^{2} - n^{2}) + (n^{2} + 2 m n) + n^{2}}}

= \sqrt{x^{m^{2} + 2 m n + n^{2}}}

= \sqrt{x^{{(m + n)}^{2}}}

= {(x^{{(m + n)}^{2}})}^{\frac{1}{2}}

= x^{m + n}

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