The-time-taken-by-a-train-l-metres-long-running-at-x-km-h-to-pass-a-man-who-is-running-at-y-km-h-in-the-direction-opposite-to-that-of-the-train-The-time-taken-to-cover-l-metres-at-km-h-

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Question Number 24417 by dhandhaliyachandra@gmail.Com last updated on 17/Nov/17

$$\mathrm{The}\mathrm{time}\mathrm{taken}\mathrm{by}\mathrm{a}\mathrm{train}l\mathrm{metres}\mathrm{long}$$$$\mathrm{running}\mathrm{at}x\mathrm{km}/\mathrm{h}\mathrm{to}\mathrm{pass}\mathrm{a}\mathrm{man}\mathrm{who}$$$$\mathrm{is}\mathrm{running}\mathrm{at}y\mathrm{km}/\mathrm{h}\mathrm{in}\mathrm{the}\mathrm{direction}$$$$\mathrm{opposite}\mathrm{to}\mathrm{that}\mathrm{of}\mathrm{the}\mathrm{train}=\mathrm{The}\mathrm{time}$$$$\mathrm{taken}\mathrm{to}\mathrm{cover}l\mathrm{metres}\mathrm{at}\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{km}/\mathrm{h}.$$

Answered by ajfour last updated on 17/Nov/17

$$(x+y)$$

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