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Question Number 97658 by Vishal Sharma last updated on 09/Jun/20
The value of cos ((2π)/7) +cos ((4π)/7)+cos ((6π)/7)  is
Thevalueofcos2π7+cos4π7+cos6π7is
Commented by bemath last updated on 09/Jun/20
x=((2π)/7)   ((cos x+cos 2x+cos 3x)/(2sin x))× 2sin x  ((sin 2x+2sinx cos 2x+2sin xcos 3x )/(2sin x)) =  ((sin 2x+sin 3x−sin x+sin 4x−sin 2x)/(2sin x)) =  ((sin 4x+sin 3x−sin x)/(2sin x)) =  ((2sin (((7x)/2)) cos ((x/2))−sin x)/(2sin x)) = −(1/2)  [ sin (((7x)/2)) = sin π = 0 ]
x=2π7cosx+cos2x+cos3x2sinx×2sinxsin2x+2sinxcos2x+2sinxcos3x2sinx=sin2x+sin3xsinx+sin4xsin2x2sinx=sin4x+sin3xsinx2sinx=2sin(7x2)cos(x2)sinx2sinx=12[sin(7x2)=sinπ=0]

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